8.1 . body mass 2 kg falls freely without initial velocity from a height 5 m onto a horizontal surface and bounces off it at a speed 5 m/s. Find the absolute value of the change in momentum of the body upon impact.

Clue

Momentum is a vector quantity, first of all, the change in momentum is the difference of vector quantities. Mandatory projection on the selected coordinate axis. Determine the speed at the moment the body falls from a height 5 m using kinematic equations.

If inelastic, then the total momentum of the system before a collision can be determined using the Pythagorean theorem. Since two colliding objects are moving together in the same direction after the collision, the total momentum is simply the total mass of the objects multiplied by their speed. A problem plus problem is a type of problem in which the analysis and solution involve a combination of the principles of conservation of momentum and other principles of mechanics. Such a problem usually involves two analyzes that need to be done separately.

Answer

30 kg.m/s

8.2 . ball mass 200 g flew at speed 20 m/s. After hitting the wall, it rebounded at a right angle to the previous direction with a speed 15 m/s

Clue

Draw a picture for the problem. Find the difference between the vectors of the final and initial impulses. Use, for example, the Pythagorean theorem.

Answer

One of the analyzes is collision analysis to determine the speed of one of the colliding objects before or after the collision. These two models allow the student to predict how far an object will travel or how far it will roll after colliding with another object.

Effective problem solving habits

When solving momentum and problems, it is important to take the time to identify known and unknown quantities. An effective habit problem solver approaches a physics problem in a way that reflects a collection of disciplined habits. While not every effective problem solver takes the same approach, everyone has habits that they share. These habits are briefly described here.

8.3 . Balls masses 1 kg and 2 kg moving parallel to each other in the same direction with speeds 4 m/s and 6 m/s respectively. What is the total momentum of these two balls?

Clue

Draw a picture for the problem. Find the sum of the vectors of the final and initial momentum of the balls. The balls move in the same direction and their projections will be of the same sign.

Which of the following statements is true about momentum? Momentum is a stored quantity; the momentum of an object never changes. The momentum of an object changes directly with the speed of the object. Two objects of different masses are moving at the same speed; a more massive object will have the most momentum. A less massive object can never have more momentum than a more massive object. Two identical objects are moving in opposite directions at the same speed. The front moving object will have the most momentum. An object with a changing speed will have a changing momentum.

  • Momentum is a vector quantity.
  • The standard unit for momentum is the Joule.
  • An object with mass will have momentum.
  • An object moving at a constant speed has momentum.
  • The object may move east and slow down; its momentum to the west.
Sliding Friction and Impulse Momentum Now that we've learned a lot about sliding friction, we'll look at momentum.

Answer

16 kg.m/s

8.4 2 kg moving towards each other. Single ball speed 3 m/s, other 7 m/s. Find the value total impulse two balls.

Clue

Draw a picture for the problem. Find the difference between the vectors of the final and initial momentum of the balls. The balls move in opposite directions along the axis and their projections will have different signs.

This is an important aspect of physics because momentum is the key to success in hockey. We'll look at puck shooting later, as it's an application of momentum. A simple definition of momentum is similar to what Newton states: momentum is "momentum".

Since speed is a vector, momentum is a vector. The game of hockey consists of many checks and fights. In the test, a player with more momentum will beat the opponent. Also, a heavy player who moves slowly may have less momentum compared to a lighter player who skates faster. It takes force to change the value or direction of movement. Newton states that the rate of change of a body's momentum is proportional to the net force applied to it.

Answer

8.5 . Two identical balls with masses 3 kg moving in mutually perpendicular directions with velocities 3 m/s and 4 m/s. What is the total momentum of this system?

Clue

Draw a picture for the problem. Determine the momentum of each ball and apply the Pythagorean theorem.

Answer

15 kg.m/s

8.6 . Ball mass 0.1 kg fell on a horizontal platform, having at the time of the fall the speed 10 m/s. Find the change in momentum of the ball during a perfectly inelastic impact. In your answer, indicate the modulus of the received value.

Momentum is the product of force and time of the force. In addition, the total change in momentum is equal to the momentum. The impulse can be carried out by a large force acting for a short time or by a small force. acting for a long time. This concept is important when we are dealing with shooting.

In the interaction of two bodies, one exerts a force on the other, and the momentum of each body changes. According to Newton's third law of motion, both impulses in any time interval are equal and opposite. This principle is easier to understand by defining the total momentum of the system as the sum of the individual bodies. When two bodies only interact with each other, their total momentum is constant. When there are no external forces, or the net external forces are zero, the total momentum of the system is constant in magnitude and direction.

Clue

Draw a picture for the problem. In a perfectly inelastic impact, the ball stops.

Answer

8.7 . bullet mass 10 g pierced the wall, while its speed decreased from 800 m/s before 400 m/s. Find the change in momentum of the bullet. In your answer, indicate the modulus of the received value.

Clue

Draw a picture for the problem. The direction of the bullet's momentum does not change. Find the difference of vectors, project them onto the selected coordinate axis.

This is a statement of the "Principle of Conservation of Linear Momentum". When no resultant external force does not act on the system, the total momentum of the system remains constant in magnitude and direction. Basic setup for the two-body problem. Many situations involve the interaction of two objects. For example, one object may be standing still while another that is moving collides with it. Or two objects can be spaced apart inner strength between them, possibly secured by a spring. In such cases, as in all cases of closed systems, momentum is conserved.

Answer

8.8 . Ball mass 0.2 kg fell freely on a horizontal platform, having at the time of the fall the speed 15 m/s. Find the change in momentum of the ball during a perfectly elastic impact. In your answer, indicate the modulus of the received value.

Clue

Draw a picture for the problem. With an absolutely elastic impact, the direction of the ball's velocity vector changes to the opposite (it falls perpendicular to the site), the velocity value is preserved.

That is, the momentum present in the system before the interaction is the exact amount of momentum present after the interaction, be it a collision or an explosion. The analysis of either of the two body momentum problems usually starts with the same initial equations. These first few equations say the same thing: the total momentum of the system before the interaction is equal to the total momentum after the interaction. At first we will think only in one dimension. Later, these same ideas will move on to more complex problems related to two-dimensional and three-dimensional motion.

Answer

8.9 . body mass 1 kg rotates uniformly around a circle with a radius 1m with angular velocity 2 rad/s. Find the modulus of change in the momentum of the body when the radius vector drawn from the center of the circle to the body is rotated by 180°.

Clue

Draw a picture for the problem. Project the initial and final momentum vectors of the body and find their modulus of change.

Here initial equations, which can be used to understand the conservation of momentum in the two-body problem. The first line is true regardless of the number of objects in the system. This total amount of momentum does not change in size or direction. After any interaction, the same size pulse in the same direction as before. Thus the first line is often quickly stated as "the total momentum before this is equal to the total momentum after". On the second line, we show the total impulse as the sum of the individual impulses for each object in the system.

Answer

8.10 . body mass 2 kg moved in a circle, and at some point it had a speed 4 m/s. After passing a quarter of the circle, the body has gained speed 3 m/s. Determine the modulus of change in body momentum.

Clue

Draw a picture for the problem. Transfer the momentum vectors of the body to one point and find the change (difference) of the vectors. Apply the Pythagorean theorem.

We are discussing a two-body system, so index 1 refers to one of the objects and index 2 refers to the other. The sum of the individual impulses before the interaction is equal to the sum of the individual impulses after. Don't confuse this to mean something like the momentum for the first object before the interaction is equal to the momentum for the first object after the interaction. Each object can and is likely to change its individual momentum. However, the sum of all impulses before that will be equal to the sum of all of them after the interaction.

The third line simply sets each individual pulse as the corresponding mass multiplies the corresponding speed for each object. Most two-body problems come from here by entering values ​​or considering special conditions from this line. Check out the examples on the following pages to see how it works.

Answer

10 kg.m/s

8.11 . ball mass 200 g flew at speed 25 m/s. After hitting the wall, it rebounded at an angle of 120 o to the previous direction with a speed 15 m/s. Find the modulus of change in the momentum of the ball upon impact.

Clue

Draw a picture for the problem. Find the difference between the vectors of the final and initial impulses. Use, for example, the Cosine Theorem.